Since you have learned Modular Arithmetic, you know how to
    work with quotients and remainders. For every pair of integers
    $a$ and $m$ with $m>0$, there exist unique integers
    $q$ and $r$ such that $a = m\cdot q+r$ and $0 \leq r < m$. But this is a bit
    simple, you wonder if you can do something more interesting
    with this theory.
    Right now, you are holding a handful of consecutive cards
    numbered from $L$ to
    $R$. You lay the cards out
    side-by-side to create a single large number (i.e.
    concatenating the digits of your cards). You would like to know
    the remainder (which is the $r$ in $a = m\cdot q + r$) when this number
    is divided by $9$. For
    example, $L = 9$ and
    $R = 11$ means you are
    holding cards $9, 10, 11$.
    Concatenating these numbers produces the number $91011$. The remainder $r$ left upon dividing this number by
    $9$ would be $r = 3$.
    Input
    Input consists of a single line containing two integers
    $L$ ($1 \leq L \leq 10^{12}$) and
    $R$ ($L \leq R \leq 10^{12}$). This means
    you are holding the cards with numbers from $L$ to $R$, inclusive.
    Output
    Display a single line containing the remainder of the
    concatenated number if you were to divide it by $9$.
    
      
        | Sample Input 1 | 
        Sample Output 1 | 
      
      
        
          2 5
 
         | 
        
          5
 
         | 
      
    
    
      
        | Sample Input 2 | 
        Sample Output 2 | 
      
      
        
          3 10
 
         | 
        
          7
 
         | 
      
    
    
      
        | Sample Input 3 | 
        Sample Output 3 | 
      
      
        
          3 100
 
         | 
        
          7
 
         | 
      
    
    
      
        | Sample Input 4 | 
        Sample Output 4 | 
      
      
        
          1000000000 1000000007
 
         | 
        
          0
 
         | 
      
    
    
      
        | Sample Input 5 | 
        Sample Output 5 | 
      
      
        
          9 11
 
         | 
        
          3
 
         |